Client-side-again
Point: 200
Category
Web Exploitation
Question
Can you break into this super secure portal? https://2019shell1.picoctf.com/problem/21886/ (link) or http://2019shell1.picoctf.com:21886
Hint
What is [obfuscation](https://en.wikipedia.org/wiki/Obfuscation_(software))?
Solution
Check the source code, we have a obfuscation JS file.
<html>
<head>
<title>Secure Login Portal V2.0</title>
</head>
<body background="barbed_wire.jpeg" >
<!-- standard MD5 implementation -->
<script type="text/javascript" src="md5.js"></script>
<script type="text/javascript">
var _0x5a46=['9f266}','_again_1','this','Password\x20Verified','Incorrect\x20password','getElementById','value','substring','picoCTF{','not_this'];(function(_0x4bd822,_0x2bd6f7){var _0xb4bdb3=function(_0x1d68f6){while(--_0x1d68f6){_0x4bd822['push'](_0x4bd822['shift']());}};_0xb4bdb3(++_0x2bd6f7);}(_0x5a46,0x1b3));var _0x4b5b=function(_0x2d8f05,_0x4b81bb){_0x2d8f05=_0x2d8f05-0x0;var _0x4d74cb=_0x5a46[_0x2d8f05];return _0x4d74cb;};function verify(){checkpass=document[_0x4b5b('0x0')]('pass')[_0x4b5b('0x1')];split=0x4;if(checkpass[_0x4b5b('0x2')](0x0,split*0x2)==_0x4b5b('0x3')){if(checkpass[_0x4b5b('0x2')](0x7,0x9)=='{n'){if(checkpass[_0x4b5b('0x2')](split*0x2,split*0x2*0x2)==_0x4b5b('0x4')){if(checkpass[_0x4b5b('0x2')](0x3,0x6)=='oCT'){if(checkpass[_0x4b5b('0x2')](split*0x3*0x2,split*0x4*0x2)==_0x4b5b('0x5')){if(checkpass['substring'](0x6,0xb)=='F{not'){if(checkpass[_0x4b5b('0x2')](split*0x2*0x2,split*0x3*0x2)==_0x4b5b('0x6')){if(checkpass[_0x4b5b('0x2')](0xc,0x10)==_0x4b5b('0x7')){alert(_0x4b5b('0x8'));}}}}}}}}else{alert(_0x4b5b('0x9'));}}
</script>
<div style="position:relative; padding:5px;top:50px; left:38%; width:350px; height:140px; background-color:gray">
<div style="text-align:center">
<p>New and Improved Login</p>
<p>Enter valid credentials to proceed</p>
<form action="index.html" method="post">
<input type="password" id="pass" size="8" />
<br/>
<input type="submit" value="verify" onclick="verify(); return false;" />
</form>
</div>
</div>
</body>
</html>Go to Chrome Developer Tools and then move to source tab. Then click to index.html and click to {} in the left of bottom to show pretty print. Then we have this code below.
So We've writen some code to translate it. Then run this code in console.
Finally we've got flag.
Flag
picoCTF{not_this_again_19f266}
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